# Solving Percentage Word Problems Example 47% of the students in a class of 34 students has glasses or contacts.How many students in the class have either glasses or contacts?Since this is a TEKS readiness skill and a skill with heavy real-world application, I think that it is important to spend several days covering it.

Example 47% of the students in a class of 34 students has glasses or contacts.How many students in the class have either glasses or contacts?Since this is a TEKS readiness skill and a skill with heavy real-world application, I think that it is important to spend several days covering it.

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When I begin to teach part, whole, and percent problems, I explain to my students that there is nothing that I teach in my class that I use more often in my real life.

Students reflect on where they see percents: the grocery store, sales and discounts, and their grades.

$$\frac=\frac$$ $$\frac\cdot =\frac\cdot b$$ $$a=\frac\cdot b$$ x/100 is called the rate.

$$a=r\cdot b\Rightarrow Percent=Rate\cdot Base$$ Where the base is the original value and the percentage is the new value.

You will be given two of the values, or at least enough information that you can figure two of them out.

Then you'll need to pick a variable for the value you don't have, write an equation, and solve for that variable.Typically, I give students three problems that are very similar and ask them, “Are we solving for the part, for the whole, or for the percent?” Allow students to grapple with the three different problems and ask them how they know. If a student can decipher what they are solving for and what the given information is, then it just becomes a multiplication and division problem.In addition, an anchor chart that lists all of the factor pairs of 100 can really help students who struggle solving the proportion using a scale factor.You can see tips on how to teach inequalities, proportional reasoning, ratios, and fractions/decimals/percents. What other middle school math concepts would you like for us to write about?Consider using my prefered problem solving model here. Students are used to having at least three numbers and solving for an unknown fourth when solving proportion word problems.This can be a bit of a slippery slope as they get older and the problems get more complex, or if there is a table involved.The format displayed above, "(this number) is (some percent) of (that number)", always holds true for percents.In any given problem, you plug your known values into this equation, and then you solve for whatever is left.$$a=r\cdot b$$ $\%=0.47a=0.47\cdot 34a=15.98\approx 16$\$ 16 of the students wear either glasses or contacts.We often get reports about how much something has increased or decreased as a percent of change.

## Comments Solving Percentage Word Problems

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